Don't error when attempting to sort on an object field (#4806)

* add failing test to demonstrate that you can't sort on a
field in an object.

* Only validate the base of the field name.

* fix test name

* Only test sort for mongo.

* pg order by nested object

* level 2 test

* Factor out operation to get a field's base name.  Add comment.

* tweak comment wording so it wont make my grammar teacher angry.
This commit is contained in:
Arthur Cinader
2018-06-07 15:47:18 -07:00
committed by Florent Vilmart
parent cf3a872e67
commit e06471603f
3 changed files with 101 additions and 5 deletions

View File

@@ -294,6 +294,16 @@ const untransformObjectACL = ({_rperm, _wperm, ...output}) => {
return output;
}
/**
* When querying, the fieldName may be compound, extract the base fieldName
* `temperature.celsius` becomes `temperature`
* @param {string} fieldName that may be a compound field name
* @returns {string} the basename of the field
*/
const getBaseFieldName = (fieldName: string): string => {
return fieldName.split('.')[0]
}
const relationSchema = { fields: { relatedId: { type: 'String' }, owningId: { type: 'String' } } };
class DatabaseController {
@@ -411,8 +421,8 @@ class DatabaseController {
if (fieldName.match(/^authData\.([a-zA-Z0-9_]+)\.id$/)) {
throw new Parse.Error(Parse.Error.INVALID_KEY_NAME, `Invalid field name for update: ${fieldName}`);
}
fieldName = fieldName.split('.')[0];
if (!SchemaController.fieldNameIsValid(fieldName) && !isSpecialUpdateKey(fieldName)) {
const baseFieldName = getBaseFieldName(fieldName);
if (!SchemaController.fieldNameIsValid(baseFieldName) && !isSpecialUpdateKey(baseFieldName)) {
throw new Parse.Error(Parse.Error.INVALID_KEY_NAME, `Invalid field name for update: ${fieldName}`);
}
});
@@ -900,7 +910,8 @@ class DatabaseController {
if (fieldName.match(/^authData\.([a-zA-Z0-9_]+)\.id$/)) {
throw new Parse.Error(Parse.Error.INVALID_KEY_NAME, `Cannot sort by ${fieldName}`);
}
if (!SchemaController.fieldNameIsValid(fieldName)) {
const baseFieldName = getBaseFieldName(fieldName);
if (!SchemaController.fieldNameIsValid(baseFieldName)) {
throw new Parse.Error(Parse.Error.INVALID_KEY_NAME, `Invalid field name: ${fieldName}.`);
}
});