fix: relation constraints in compound queries Parse.Query.or, Parse.Query.and not working (#8203)

This commit is contained in:
dblythy
2022-10-24 21:45:17 +11:00
committed by GitHub
parent fb503320c3
commit 28f0d26677
2 changed files with 55 additions and 12 deletions

View File

@@ -410,6 +410,49 @@ describe('Parse.Relation testing', () => {
});
});
it('or queries with base constraint on relation field', async () => {
const ChildObject = Parse.Object.extend('ChildObject');
const childObjects = [];
for (let i = 0; i < 10; i++) {
childObjects.push(new ChildObject({ x: i }));
}
await Parse.Object.saveAll(childObjects);
const ParentObject = Parse.Object.extend('ParentObject');
const parent = new ParentObject();
parent.set('x', 4);
const relation = parent.relation('toChilds');
relation.add(childObjects[0]);
relation.add(childObjects[1]);
relation.add(childObjects[2]);
const parent2 = new ParentObject();
parent2.set('x', 3);
const relation2 = parent2.relation('toChilds');
relation2.add(childObjects[0]);
relation2.add(childObjects[1]);
relation2.add(childObjects[2]);
const parents = [];
parents.push(parent);
parents.push(parent2);
parents.push(new ParentObject());
await Parse.Object.saveAll(parents);
const query1 = new Parse.Query(ParentObject);
query1.equalTo('x', 4);
const query2 = new Parse.Query(ParentObject);
query2.equalTo('x', 3);
const query = Parse.Query.or(query1, query2);
query.equalTo('toChilds', childObjects[2]);
const list = await query.find();
const objectIds = list.map(item => item.id);
expect(objectIds.indexOf(parent.id)).not.toBe(-1);
expect(objectIds.indexOf(parent2.id)).not.toBe(-1);
equal(list.length, 2, 'There should be 2 results');
});
it('Get query on relation using un-fetched parent object', done => {
// Setup data model
const Wheel = Parse.Object.extend('Wheel');